Optimal. Leaf size=400 \[ \frac{10 a^2 b^2 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+7} (a e+b d)}{f^7 (m+7) \left (a+b x^2\right )}+\frac{b^5 e \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+13}}{f^{13} (m+13) \left (a+b x^2\right )}+\frac{b^4 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+11} (5 a e+b d)}{f^{11} (m+11) \left (a+b x^2\right )}+\frac{5 a b^3 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+9} (2 a e+b d)}{f^9 (m+9) \left (a+b x^2\right )}+\frac{a^5 d \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+1}}{f (m+1) \left (a+b x^2\right )}+\frac{a^4 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+3} (a e+5 b d)}{f^3 (m+3) \left (a+b x^2\right )}+\frac{5 a^3 b \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+5} (a e+2 b d)}{f^5 (m+5) \left (a+b x^2\right )} \]
[Out]
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Rubi [A] time = 0.587138, antiderivative size = 400, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.057 \[ \frac{10 a^2 b^2 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+7} (a e+b d)}{f^7 (m+7) \left (a+b x^2\right )}+\frac{b^5 e \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+13}}{f^{13} (m+13) \left (a+b x^2\right )}+\frac{b^4 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+11} (5 a e+b d)}{f^{11} (m+11) \left (a+b x^2\right )}+\frac{5 a b^3 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+9} (2 a e+b d)}{f^9 (m+9) \left (a+b x^2\right )}+\frac{a^5 d \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+1}}{f (m+1) \left (a+b x^2\right )}+\frac{a^4 \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+3} (a e+5 b d)}{f^3 (m+3) \left (a+b x^2\right )}+\frac{5 a^3 b \sqrt{a^2+2 a b x^2+b^2 x^4} (f x)^{m+5} (a e+2 b d)}{f^5 (m+5) \left (a+b x^2\right )} \]
Antiderivative was successfully verified.
[In] Int[(f*x)^m*(d + e*x^2)*(a^2 + 2*a*b*x^2 + b^2*x^4)^(5/2),x]
[Out]
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Rubi in Sympy [A] time = 85.5961, size = 374, normalized size = 0.94 \[ \frac{a^{5} d \left (f x\right )^{m + 1} \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f \left (a + b x^{2}\right ) \left (m + 1\right )} + \frac{a^{4} \left (f x\right )^{m + 3} \left (a e + 5 b d\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{3} \left (a + b x^{2}\right ) \left (m + 3\right )} + \frac{5 a^{3} b \left (f x\right )^{m + 5} \left (a e + 2 b d\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{5} \left (a + b x^{2}\right ) \left (m + 5\right )} + \frac{10 a^{2} b^{2} \left (f x\right )^{m + 7} \left (a e + b d\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{7} \left (a + b x^{2}\right ) \left (m + 7\right )} + \frac{5 a b^{3} \left (f x\right )^{m + 9} \left (2 a e + b d\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{9} \left (a + b x^{2}\right ) \left (m + 9\right )} + \frac{b^{5} e \left (f x\right )^{m + 13} \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{13} \left (a + b x^{2}\right ) \left (m + 13\right )} + \frac{b^{4} \left (f x\right )^{m + 11} \left (5 a e + b d\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{f^{11} \left (a + b x^{2}\right ) \left (m + 11\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((f*x)**m*(e*x**2+d)*(b**2*x**4+2*a*b*x**2+a**2)**(5/2),x)
[Out]
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Mathematica [A] time = 0.302714, size = 160, normalized size = 0.4 \[ \frac{\sqrt{\left (a+b x^2\right )^2} (f x)^m \left (\frac{a^5 d x}{m+1}+\frac{a^4 x^3 (a e+5 b d)}{m+3}+\frac{5 a^3 b x^5 (a e+2 b d)}{m+5}+\frac{10 a^2 b^2 x^7 (a e+b d)}{m+7}+\frac{b^4 x^{11} (5 a e+b d)}{m+11}+\frac{5 a b^3 x^9 (2 a e+b d)}{m+9}+\frac{b^5 e x^{13}}{m+13}\right )}{a+b x^2} \]
Antiderivative was successfully verified.
[In] Integrate[(f*x)^m*(d + e*x^2)*(a^2 + 2*a*b*x^2 + b^2*x^4)^(5/2),x]
[Out]
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Maple [B] time = 0.014, size = 1099, normalized size = 2.8 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((f*x)^m*(e*x^2+d)*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x)
[Out]
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Maxima [A] time = 0.736163, size = 663, normalized size = 1.66 \[ \frac{{\left ({\left (m^{5} + 25 \, m^{4} + 230 \, m^{3} + 950 \, m^{2} + 1689 \, m + 945\right )} b^{5} f^{m} x^{11} + 5 \,{\left (m^{5} + 27 \, m^{4} + 262 \, m^{3} + 1122 \, m^{2} + 2041 \, m + 1155\right )} a b^{4} f^{m} x^{9} + 10 \,{\left (m^{5} + 29 \, m^{4} + 302 \, m^{3} + 1366 \, m^{2} + 2577 \, m + 1485\right )} a^{2} b^{3} f^{m} x^{7} + 10 \,{\left (m^{5} + 31 \, m^{4} + 350 \, m^{3} + 1730 \, m^{2} + 3489 \, m + 2079\right )} a^{3} b^{2} f^{m} x^{5} + 5 \,{\left (m^{5} + 33 \, m^{4} + 406 \, m^{3} + 2262 \, m^{2} + 5353 \, m + 3465\right )} a^{4} b f^{m} x^{3} +{\left (m^{5} + 35 \, m^{4} + 470 \, m^{3} + 3010 \, m^{2} + 9129 \, m + 10395\right )} a^{5} f^{m} x\right )} d x^{m}}{m^{6} + 36 \, m^{5} + 505 \, m^{4} + 3480 \, m^{3} + 12139 \, m^{2} + 19524 \, m + 10395} + \frac{{\left ({\left (m^{5} + 35 \, m^{4} + 470 \, m^{3} + 3010 \, m^{2} + 9129 \, m + 10395\right )} b^{5} f^{m} x^{13} + 5 \,{\left (m^{5} + 37 \, m^{4} + 518 \, m^{3} + 3422 \, m^{2} + 10617 \, m + 12285\right )} a b^{4} f^{m} x^{11} + 10 \,{\left (m^{5} + 39 \, m^{4} + 574 \, m^{3} + 3954 \, m^{2} + 12673 \, m + 15015\right )} a^{2} b^{3} f^{m} x^{9} + 10 \,{\left (m^{5} + 41 \, m^{4} + 638 \, m^{3} + 4654 \, m^{2} + 15681 \, m + 19305\right )} a^{3} b^{2} f^{m} x^{7} + 5 \,{\left (m^{5} + 43 \, m^{4} + 710 \, m^{3} + 5570 \, m^{2} + 20409 \, m + 27027\right )} a^{4} b f^{m} x^{5} +{\left (m^{5} + 45 \, m^{4} + 790 \, m^{3} + 6750 \, m^{2} + 28009 \, m + 45045\right )} a^{5} f^{m} x^{3}\right )} e x^{m}}{m^{6} + 48 \, m^{5} + 925 \, m^{4} + 9120 \, m^{3} + 48259 \, m^{2} + 129072 \, m + 135135} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(5/2)*(e*x^2 + d)*(f*x)^m,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.287381, size = 1152, normalized size = 2.88 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(5/2)*(e*x^2 + d)*(f*x)^m,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((f*x)**m*(e*x**2+d)*(b**2*x**4+2*a*b*x**2+a**2)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 0.308387, size = 1, normalized size = 0. \[ \mathit{Done} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(5/2)*(e*x^2 + d)*(f*x)^m,x, algorithm="giac")
[Out]